# Derivative

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DERIVATIVE. Coming from another; taken from something preceding, secondary; as derivative title, which is that acquired from another person. There is considerable difference between an original and a derivative title. When the acquisition is original, the right thus acquired to the thing becomes property, which must be unqualified and unlimited, and since no one but the occupant has any right to the thing, he must have the whole right of disposing of it. But with regard to derivative acquisition, it may be otherwise, for the person from whom the thing is acquired may not have an unlimited right to it, or he may convey or transfer it with certain reservations of right. Derivative title must always be by contract.
2. Derivative conveyances are, those which presuppose some other precedent conveyance, and serve only to enlarge, confirm, alter, restrain, restore, or transfer the interest granted by such original conveyance, 3 Bl. Com. 321.

A Law Dictionary, Adapted to the Constitution and Laws of the United States. By John Bouvier. Published 1856.
References in periodicals archive ?
(2) Hence, the direction of third-order risk preference for u(y) is indicated by the sign of its third derivative, or equivalently by the sign of the index
From Equations (14) and (17) it can be seen that the second and third derivatives of [beta] require the first, second and third derivatives of A and the first and second derivatives of the eigenvector c.
For the third derivatives at interior nodes, the following formula is given in [23]:
For example, at [xi] = 1 the third derivative value is equal
Subsequently third order dispersion [[beta].sub.3], the third derivative of the wave vector [k.sub.z] was evaluated to be 0.055 [ps.sup.3]/km.
For example, the third derivative of the polynomial in Eq.
Indeed, if we integrate by parts and keep into account that the third derivative is constant on pieces, then [[integral].sup.b.sub.a][f".sub.s](x) x (f"(x) - [f".sub.x](x)) dx = - [[integral].sup.b.sub.a] f"'(x) x (f'(x) - [f'.sub.s](x))dx = 0, hence [[integral].sup.b.sub.a][f".sub.s](x) x f"(x)dx = [[integral].sup.b.sub.a][f".sub.s][(x).sup.2]dx, therefore

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