be stationary

See: remain, rest, stay
References in periodicals archive ?
Granger and Weiss[8] pointed out that a linear combination of two or more non-stationary series may be stationary .
This long time window may miss stationary states as vehicle may not be stationary for such a lengthy period.
The disadvantage of such long time window is the chances of missing the stationary states as the vehicle may not be stationary for such a lengthy period.
They grow slowly and usually appear to be stationary after puberty.
They were meant to be stationary. Not in A Dancer's Christmas!
critically depends on real income to be stationary. Consider the quantity theory equation
Then [r.sub.t] can be stationary only if horizons are infinite and the intergenerational discount rate is constant.
Therefore, [r.sub.t] can be stationary and [d.sub.t] and [g.sub.t] can be difference-stationary only if the level of [r.sub.t] is not related in the long run to the level of [d.sub.t] and [g.sub.t].
The restriction that [e.sub.t] be stationary is crucial.
Because [[Delta] d.sub.t] = [h.sub.d] [prime] (L) [[Upsilon].sub.t] and [[Delta] g.sub.t] = [h.sub.g] [prime] (L) [[Upsilon].sub.t], the variables of [d.sub.t] and [g.sub.t] can be stationary only if 1-L is a factor of [h.sub.d] (L); i.e., only if [h.sub.d] (1) = [h.sub.g] (1) = 0 of [h.sub.d] (L) and [h.sub.g] (L); i.e., only if [h.sub.d] (1) = [h.sub.g] (1) = 0.
Under the null hypothesis that [[Rho].sub.d] = 0 and [[Rho].sub.g] = 0, equation (43) implies that [r.sub.t] must be stationary. If either the alternative hypothesis [[Rho].sub.d] > 0 or the alternative hypothesis [[Rho].sub.g] [is not equal to] 0 holds then [r.sub.t] must be difference-stationary.